1 files changed, 26 insertions, 9 deletions

diff --git a/ws2015/oss/blaetter/07/abgabe.md b/ws2015/oss/blaetter/07/abgabe.md
index 833756d..b136b1a 100644
--- a/ws2015/oss/blaetter/07/abgabe.md
+++ b/ws2015/oss/blaetter/07/abgabe.md
@@ -7,13 +7,13 @@ header-includes:
 a)
 
 \begin{tikzpicture}
-  \draw[thick, <->] (0, 6) -- (0, 0) -- (10, 0);
+  \draw[thick, <->] (0, 6) -- (0, 0) -- (9.5, 0);
   \foreach \x in {1, 2, 3, 4, 5}
     \draw[thick] (-1pt, \x) -- (1pt, \x) node [anchor=east] {$P_{\x}$};
-  \foreach \x in {0, ..., 19}
+  \foreach \x in {0, ..., 18}
     \draw[thick] ({\x / 2}, -1pt) -- ({\x / 2}, 1pt) node [anchor=north] {$\x$};
 
-  \draw[xstep=0.5, ystep=1, gray, very thin] (0, 5) grid (9.5, 0); 
+  \draw[xstep=0.5, ystep=1, gray, very thin] (0, 5) grid (9, 0); 
 
   \draw[|-|] (0, 1) -- (1, 1);
   
@@ -26,26 +26,26 @@ a)
   \draw[|-|] (6.5, 4) -- (8, 4);
 
   \draw[|-|, dashed] (2.5, 5) -- (8, 5);
-  \draw[|-|] (8, 5) -- (9.5, 5);
+  \draw[|-|] (8, 5) -- (9, 5);
 \end{tikzpicture}
 
 b)
 
 \begin{tikzpicture}
-  \draw[thick, <->] (0, 6) -- (0, 0) -- (10, 0);
+  \draw[thick, <->] (0, 6) -- (0, 0) -- (9.5, 0);
   \foreach \x in {1, 2, 3, 4, 5}
     \draw[thick] (-1pt, \x) -- (1pt, \x) node [anchor=east] {$P_{\x}$};
-  \foreach \x in {0, ..., 19}
+  \foreach \x in {0, ..., 18}
     \draw[thick] ({\x / 2}, -1pt) -- ({\x / 2}, 1pt) node [anchor=north] {$\x$};
 
-  \draw[xstep=0.5, ystep=1, gray, very thin] (0, 5) grid (9.5, 0); 
+  \draw[xstep=0.5, ystep=1, gray, very thin] (0, 5) grid (9, 0); 
 
   \draw[|-|] (0, 1) -- (1, 1);
 
   \draw[|-|] (1, 2) -- (3, 2);
 
   \draw[|-|, dashed] (1, 3) -- (5.5, 3);
-  \draw[|-|] (5.5, 3) -- (9.5, 3);
+  \draw[|-|] (5.5, 3) -- (9, 3);
 
   \draw[|-|, dashed] (2, 4) -- (4, 4);
   \draw[|-|] (4, 4) -- (5.5, 4);
@@ -54,5 +54,22 @@ b)
   \draw[|-|] (3, 5) -- (4, 5);
 \end{tikzpicture}
 
-c)
+c) Es seien $W(P_n)$, $V(P_n)$, $W^\prime(P_n)$, und $V^\prime(P_n)$ die Wartezeit und die Verweilzeit des Prozesses $P_n$ für FCFS und SJF.
 
+\begin{align*}
+\frac{\sum_{i = 1}^n W(P_n)}{5} &= \frac{0 + 0 + 4 + 9 + 11}{5} = \frac{24}{5} = 4.8 \\
+\frac{\sum_{i = 1}^n V(P_n)}{5} &= \frac{2 + 4 + 11 + 12 + 14}{5} = \frac{43}{5} = 8.6
+\\
+\frac{\sum_{i = 1}^n W^\prime(P_n)}{5} &= \frac{0 + 0 + 9 + 4 + 1}{5} = \frac{14}{5} = 2.8 \\
+\frac{\sum_{i = 1}^n V^\prime(P_n)}{5} &= \frac{2 + 4 + 16 + 7 + 3}{5} = \frac{35}{5} = 7
+\end{align*}
+
+d) Prozesse, die, laut Scheduler, lange Bedienzeiten haben verweilen sehr lange, da sie lange warten.
+
+# Prozesse und Threads
+
+a) running
+b) *ein Prozess, kein Thread* wird als equivalent gesehen zu *kein Prozess*
+c) Threads teilen sich innerhalb eines Prozesses einen Adressraum, Daten sind nicht *sicher*.
+d) suspended
+e) Zuordnung mehrer Treads eines Prozesses auf verschiedene Prozessoren